CHESS

Rotorua Morning Post, Volume 3, Issue 617, 23 August 1933, Page 6

CHESS

"Ruy

Lopez.")

GENERAL JOTTINGS RESULTS OF VARIOUS GAMES DURING WEEK SENIOR CHAMPIONSHIP (Specially written for the "Morning

Post" by

The following are the results of the tenth round of the senior championships : Tibbitts beat Vinall, Watson beat Edwards, Kurney beat Tattersall, Andrews beat Jackson. Burton v. Saxby was adjourned and Clark v. Roland was postponed. Fraer and Paterson had byes. Burton beat Vinall in the ninth round. Juniors: W. Heley he'at Rowley, Dixon beat Jenkins, Lenihan beat Musgrave. Evans v. H. Heley was postponed. Blencowe and Bould had byes. In the ninth round Dixon beat Bailey and W. Heley beat Evans. Tibbitts, Watson and Kurney were at the top of their form and disposed of their respective opponents fairly quickly. Jackson walked right into a neat little trap set for him by1 Andrews, and was forced to resigri soon afterwards. At the adjournment Burton and/ Saxby are even in material and position, but on, the complications which appear likely to ensue, Saxby, who has so far played a fine defence, will need the 20 minutes he is up on Burton on the clock. Eleventh Round The draw for the eleventh round: Senior — Heywlood v. Jiackson,: Kurney v. Paterson, Roland v. Tattersall, Edwards v. Clark, Vinall v. Watson, Saxby v. Tibbitts, and Fraer v. Burton. Andrews and Booth have byes. Juniors. Martin v. Musgrave, Bailey v. Mulligan, Jenkins v. Shaw, W. Heley v. Dixon, H. Heley v. Rowley, Bould v. Evans (postponed). Blencowe and Lenihan have byes. The eleventh round will be played on Friday next, players mentioned first having the move. A Eamous Game of Chess Every chess player should know the brilliant game of Paul Morphy's which he played against the Duke of Brunswick and Count Isouard in the Royal Box at the Paris Opera, in 1858, during a performance of the "Barber of Seville." Morphy played White, the game being as f ollows: 1P - K4, P - K4;. 2Kt - KB3, P - Q3; 3P - Q4, B - KKt5; 4P x P, B x Kt; 5Q x B, P x P; 6B - QB4, Kt - KB3-; 7Q - QKt3, Q - K2; 8Kt - QB3, P - QB3; 9B - KKt5, P - QKt4; lOKt x KtP, P x Kt; 11B x KtPch. QKt _ Q2; 12. 0-0-0, R - Ql; 13R x Kt, R x R; 14R - Ql, Q - K3; 15B x Rch., Kt x B; 16Q - Kt8 eh., Kt x Q; 17R - Q8 mate. Black's second move, it should be noticed, shuts in his King's Bishop, but his chief mistake is his third move for he is forced to take the Knight on his fourth move. Why? Notice White's sacrifice of his Knight on his tenth move, enabling him to conduct an immediate attack on Black's cramped King. Again, White on his thirteenth move maintained the pin; had he played B x Kt ch. it would have been much easier for Black. This game is worth studying, and the time spent will be amply repaid. Combination and Position Players 'These two opposing types of players are aptly described by Lasker in his "Manual of Chess" as f ollows: — "The combinative player is an adventurer, speculator, gambler, the position player believing in rigid dogma, happy only in a firm position, afraid of all dangers, parsimonious with all he holds, even with the minute values; the former perhaps careless of detail and large visioned, the latter penny wise and pound foolish. The combinative player calls the position player Philistine, pedant, woodshifter; the position player replies with invectives such as romancer, dreamer, presumptuous idealist." Chess Masters of To-day Jose Raul Capablanca was born in Havana on November 19, 1888. He was not five when he first learnt the moves of chess, and has been playing practically ever since. In 1909 by defeating Marshall he became virtual Pan-American champion, and in 1921 by defeating Lasker he became chess champion of the world. Lasker resigned after the 14th game, when the score stood at 4-0 against him with 10 draws. In 1927 he lost the title to Alekhin, and whilst a return match has often been mooted, nothing has eventuated. This Week's Problem White mates in two moves. Posk tion: kr4Rl, pb6, 8, 3B4, 8, 6K1, Q7, 8. Check position: White - K on KKt3, Q on QR2, R on KKt8, B on Q5. Black - K on QR1, R on QKtl, B on QKt2, and P on QR2. (by F. Schruffer). Solution to last week's problem: 1B - B7. (by Chocholous.)