LAST WEEK'S SOLUTIONS.
A "Measure" Puzzle. —The "pourings" can be done in eleven operations. ./ Dividing £3 4s 2d— "X" 14, 25s 8d; "V" 12, 225; and "Z" 9, 16s 6d; total, £3 4s 2d; A Puzzle with Counters. —Any three from one side may be combined, with one on the other in IQO ways, and of course the 4 removed may be arranged by permutation in 24 ways making-2400 altogether.
The Shortest Route. —Produce the west boundary to a point so that the . distance from there to the north-west corner is the same as the distance from the corner to where the man was working. Then a line drawn from the extended point to tho house would pass through the mailbox,
which makes that point the shortest route to the house from the point where the farmer was working, via the north boundary.
The Size of a Sheep Pen.—On the basis of 13 sheep to six square yards the first oblong enclosure was twenty-four hurdles by one. But the same fifty hurdles could be erected in the form of an approximate square twelve hurdles by thirteen which would hold the extra 286 ewes making 338 altogether in a peu of exactly 156 square yards, sufficient on the basis mentioned. No extra hurdles would therefore be required.
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Bibliographic details
Evening Post, Volume CXV, Issue 71, 25 March 1933, Page 9
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216LAST WEEK'S SOLUTIONS. Evening Post, Volume CXV, Issue 71, 25 March 1933, Page 9
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