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PUZZLE COLUMN.

ANSWERS TO PUZZLES.

TflE >IVE OLAS'ZS FROBLEM.

N. C. writes :— I submit the following as an answer to Annie Magee's problem : Pat 7 aoholars m one class, 3 In another, 5 In another, and 3 In another, then shava the head of the 2 remaining. She will then ba~ve an odd number m each olsbb, because the fifth olais will oontaln only odd vnpl-s.

(Our correspondent's solution Is Ingenious, and perhaps Annie Magee will say If it Is orrt ck. — Ed )

XHB Sf.YENTi-BN ELEPHANTS

M s Halaall, Hampstead, sends the following as tha answer :— '•• He has to borrow an elephant, which be places wlt!F the 17, making thus 18 In all. Then to the eldest son be glvßß 9, viz , one-half 'he nnmber, to the second 6 (one-third), and to the youngest 2 (one-ninth), acoordlag to th 9 will. He than takes home his own elephmt." James Smith, Tlawald, also sends the ••ma solution.

(Toe eolation above given' la correct, but tbere Is a fallaoy In the argument; The Rajth's will left $+£+ one-ninth of<£ 17, wbioh eqaali 16 one-eighteenth, ; whereas the whole 17 elephants were 5 diiposed of. — Ed.) ' ".'

THE WBtQHTS PDZZMS. . . !. , The answer la that the four weights used would be respectively a lib, 3 b, 91b, and 271 b, The pf Inolple is • (?eo»«t8o«l > progression, beginning with 1 and mnltiplying It hy the first, second, and third powers of 3 for the nrxt three no tubers.

Permanent link to this item
Hononga pūmau ki tēnei tūemi

https://paperspast.natlib.govt.nz/newspapers/AG18880929.2.16

Bibliographic details
Ngā taipitopito pukapuka

Ashburton Guardian, Volume VII, Issue 1957, 29 September 1888, Page 2

Word count
Tapeke kupu
240

PUZZLE COLUMN. Ashburton Guardian, Volume VII, Issue 1957, 29 September 1888, Page 2

PUZZLE COLUMN. Ashburton Guardian, Volume VII, Issue 1957, 29 September 1888, Page 2

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