A NUMBER CROSSWORD PUZZLE

New Zealand Listener, Volume 13, Issue 321, 17 August 1945, Page 11

A NUMBER CROSSWORD PUZZLE

10 ACROSS ‘is the product of the prime number 5 ACROSS and 8 ACROSS; it is also the difference of the cubes of 6 DOWN REVERSED and 1 ACROSS; it is also the difference of the squares of 2 DOWN and 7 DOWN REVERSED. -The digits of 2 DOWN add up to nineteen, and two of them are the same; so are two of those of 7 DOWN, which is a multiple of nine. , The digits of 6 DOWN are in arithmetical progression. 5 DOWN is the product of four consecutive prime numbers, 9 ACROSS being the square of one of them, and forming the beginning of 2 DOWN. 3 DOWN and 4 DOWN are both multiples of 13 ACROSS, and the top half of each is half its bottom half. Also 4 DOWN has as factors two of the factors of, 5 DOWN. 10 DOWN is half 13 ACROSS, which is the sum of the digits in 2 DOWN and 3 DOWN together. 1 DOWN is the sum of 10 DOWN and 12 ACROSS. | 12 ACROSS is three times the sum of the digits in column 6 (i.e., the three digits in 6 DOWN and the haga in 13 ACROSS). 11 ACROSS is obtained by multiplying 1 DOWN by the sum of the digits of 5 DOWN.

N order to forestall any complaints about this week’s puzzle, let me hasten to state that it is only given by way of a change. I hope it will please a few, and I assure the many who will not be pleased that next week will see a return of the ordinary puzzle. For those who attempt this number puzzle (which, by the way, was not constructed by me), the thick lines indicate the end and/or beginning of a number. The solution can be found by a mixture of straightforward arithmetic and trial and error, although a little elementary algebra will shorten the working

considerably.

R.W.

C.

(Solution to No. 257)